How is a function returning a reference different from initializing a reference with a regular return value?
int f1() {
static int i = 10;
return i;
}
int& f2() {
static int i = 10;
return i;
}
int main() {
const int &v1 = f1();
printf("%d\n", v1);
int v2 = f2();
printf("%d\n", v2);
}
What's the difference between
int f1();
const int &v1 = f1();
and
int& f2();
int v2 = f2();
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