what will be output of this code? in line 13 what is really happening?

#include <iostream>
#include <string.h>
using namespace std;
int main() {

    int num , n , n1 , k , x = 0;
    cout << "Enter the no. of vertices: " ;
    cin >> n;
    char StorageArr[n];
    char arr[k];
     for(k = 0; k< n ; k++){
       cout<< "arr[" << k << "] : ";
       cin >> arr[k] ;
       StorageArr[n] = arr[k];
    }

    int len = sizeof(StorageArr)/ sizeof(StorageArr[0]);

    cout << "The length of the array is : " << len << endl;
     for(int i= 0 ; i< len ; i++){
       for(int j = 0; j< len ; j++ ){
            cout<<"\n\t" <<"Element at " << StorageArr[i] <<        StorageArr[j] << ": "  ;
        cin >> num;
        if(i==j && num == 0){
            x++;
        }
    }
}

if(x == len){
    cout<<"This  is a complete graph...";
}else{
    cout<< "This is not a complete graph..." ;
}

return 0;

}

ok so how is StorageArr[n] = arr[k] is working. I mean if we assign n = 5 then all the value of arr[k] will be assign to the same position StorageArr[5] or will it be that the value of arr[k] will store in StorageArr as like first on 0th pos then on 1st postion and then so on till 4th....