jeudi 4 avril 2019

Creating an unordered_map of std::functions with any arguments?

I am trying to create a unordered map of std::functions. Where a key is a string where you will look up the function you want to call and the function is the value.

I have written a small program:

#include <iostream>
#include <unordered_map>
#include <functional>
#include <string>

void func1()
{
  std::cout << "Function1 has been called." << std::endl;
}

int doMaths(int a)
{
  return a + 10;
}

int main()
{
  std::unordered_map<std::string,std::function<void()>> myMap;

  myMap["func1"] = func1;

}

This compiles just fine, and I can call the function (however I am not sure if this is the correct way of doing it) by placing:

auto mapIter = myMap.find("func1");
auto mapVal = mapIter->second;
mapVal();

That then calls the function, however I think this is at the cost of creating a new copy of the function? Please correct me if I am wrong about that.

However, if I try to do: myMap["doMaths"] = doMaths; I get a compiler error since the value in myMap is std::function<void()>> and not std::function<int(int)>>. I did get this to compile when I did: myMap["doMaths"] = std::bind(doMaths,int()); However I do not know what that actually does. And when I try to call it in the same manner as func1, I get a compiler error.

So I guess I have two questions:

How do I create an unordered_map that will take any type of function for it's value? And how do I call the function within the map without having to make a copy of the function?

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