I'm trying to implement a simple ostream_itreator, which streams every N-th element, but i get a type error
error: no type named ‘value_type’ in ‘struct std::iterator_traits<outIterator<int> >’
typedef typename iterator_traits<_OI>::value_type _ValueTypeO;
Code:
#include <iostream>
#include <vector>
#include <iterator>
template<class T>
class outIterator {
std::ostream *stream;
size_t N;
const char* delim;
size_t counter = 0;
public:
// initialization
outIterator(std::ostream& out)
: stream(&out)
, N(1)
, delim(" ")
{}
outIterator(std::ostream& out, size_t N, const char* delimiter)
: stream(&out)
, N(N)
, delim(delimiter)
{}
// =
outIterator<T>& operator= (const T& value) {
if (counter % N == 0){
*stream << value << delim;
}
return *this;
}
};
int main() {
outIterator<int> out(std::cout, 2, " ");
std::vector<int> vec {0, 1, 2, 3, 4, 5};
std::copy(vec.begin(), vec.end(), out);
return 0;
}
Also i didn't include overloadings ++ and ++(int). They increment counter and return *this. And * overloading that returns *this
Error description:
/usr/include/c++/7/bits/stl_algobase.h:378:57: error: no type named ‘value_type’ in ‘struct std::iterator_traits<outIterator<int> >’
typedef typename iterator_traits<_OI>::value_type _ValueTypeO;
^~~~~~~~~~~
/usr/include/c++/7/bits/stl_algobase.h:383:9: error: no type named ‘value_type’ in ‘struct std::iterator_traits<outIterator<int> >’
const bool __simple = (__is_trivial(_ValueTypeI)
~~~~~~~~~~~~~~~~~~~~~~~~~~
&& __is_pointer<_II>::__value
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
&& __is_pointer<_OI>::__value
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
&& __are_same<_ValueTypeI, _ValueTypeO>::__value);
^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Aucun commentaire:
Enregistrer un commentaire