I created a class, "ListElement", that contains as a single data variable an instance of the class "MyClass" which contains a dynamically allocated array.
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For ListElement I created a default constructor which delegates to a right-value constructor that initializes an instance of MyClass.
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For MyClass I created a constructor which initializes its array to an inputted value (and a default constructor which delegates to the one above with value 0). Furthermore, I included a copy and a move constructor.
I'm, however, mostly confused, why the move constructor is not called unless the datatype is casted as an r-value reference explicitly, although it is already passed as such (see below).
#include <iostream>
template <int arrSize>
class MyClass {
private:
// Data
int* a;
public:
//Constructor
MyClass(int value){
this->a = new int[arrSize];
for(unsigned int i = 0; i<arrSize; ++i){
a[i] = value;
}
std::cout << "MyClass created!" << std::endl;
}
MyClass(): MyClass(0){}
//Copy Constructor
MyClass(const MyClass<arrSize>& other){
this->a = new int[arrSize];
for(unsigned int i = 0; i<arrSize;++i){
a[i] = other.a[i];
}
std::cout << "MyClass copied!" << std:: endl;
}
//Move Constructor
MyClass(MyClass<arrSize>&& other){
this->a = other.a;
other.a = nullptr;
std::cout << "MyClass moved!" << std::endl;
}
//Destructor
~MyClass(){
delete[] this->a;
std::cout << "MyClass deleted!" << std::endl;
}
};
class ListElement {
public:
//Constructors
ListElement(MyClass<5>&& data) : data((MyClass<5>&&)data) {} // QUESTION
ListElement(): ListElement(MyClass<5>(1)){}
private:
//Data
MyClass<5> data;
};
int main() {
ListElement myZeroListElement{};
return 0;
}
Question: Why is the copy constructor called if I write for this line (see comments)?
ListElement(MyClass<5>&& data) : data(data) {}
"data" is a right-value reference, but the move constructor is only called when I explecitly cast it, so-to-say, again into a right-value reference like this:
ListElement(MyClass<5>&& data) : data((MyClass<5>&&)data) {}
GREATLY APPRECIATED!
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