Understanding how std::forward overloads work

I want to doublecheck that I have correct understanding on how forward overloads work

template< class T >
constexpr T&& forward( std::remove_reference_t<T>& t ) noexcept;

template< class T >
constexpr T&& forward( std::remove_reference_t<T>&& t ) noexcept;

If we call the forward with some local variable n, say it's int, overloads will be specified as

  constexpr int&& forward( int& t ) noexcept;   
  constexpr int&& forward( int&& t ) noexcept;

So the first one will be chosen for our case. If we call forward with just 4 overloads will be specified same, but second version will be chosen. So first overload always catch all lvalues, and second all rvalues. Correct?