Need help in converting this simple for loop into another function that's being called recursively

How to integrate the for loop with the existing function or write a new function that runs from 0 to n where n is the input from user?

//Write a program in C or C++ to Print Fibonacci Series using recursion.
#include <stdio.h>

int fib(int n)
{
    if (n == 0 || n == 1)
        return n;
    else
        return fibonacci(n - 1) + fibonacci(n - 2);
}

int main()
{
    int n;
    printf("Enter the number of elements: ");
    scanf("%d", &n);
    printf("Fibonacci Series: ");
    for (int i = 0; i < n; i++)
    {
        printf("%d", fib(i))
    }
    return 0;
}

My try:

//Write a program in C or C++ to Print Fibonacci Series using recursion.
#include <stdio.h>

int fib(int n)
{
    if (n == 0 || n == 1)
        return n;
    else
        return fib(n - 1) + fib(n - 2);
}
void rec(int n)
{
    if(n>0)
        rec(n-1);
    else
        printf("%d", fib(n));
}

int main()
{
    int n;
    printf("Enter the number of elements: ");
    scanf("%d", &n);
    printf("Fibonacci Series: ");
    // for (int i = 0; i < n; i++)
    // {
    //     printf("%d", fib(i))
    // }
    rec(n);
    return 0;
}

This took my input correctly but output was 0.

I know I can print the Fibonacci series in a single function using static int or global variables but I am not allowed to use them. So is there any other way to print the Fibonacci series using recursion in a single function? If not, that's fine, 2 different recursive functions also works.

The code to print fibonacci series using recursion and static int variables is:

void fib(int n)
{
    static int n1 = 0, n2 = 1, n3;
    if (n > 0)
    {
        n3 = n1 + n2;
        n1 = n2;
        n2 = n3;
        printf("%d ", n3);
        fib(n - 1);
    }
}
int main()
{
    int n;
    printf("Enter the number of elements: ");
    scanf("%d", &n);
    printf("Fibonacci Series: ");
    printf("0 1 ");
    fib(n - 2);
    return 0;
}