Correctly move from a data member of a temporary object

Consider the following C++-Code

#include <iostream>
using namespace std;

struct WrapMe
{
    WrapMe() { cout << "WrapMe Default Ctor of: " << this << endl; }
    WrapMe(const WrapMe& other) { cout << "WrapMe Copy Ctor of " << this << " from " << &other << endl; }
    WrapMe(WrapMe&& other) noexcept { cout << "WrapMe Move Ctor of " << this << " from " << &other << endl; }
    ~WrapMe() { cout << "Wrap Me Dtor of" << this << endl; }
};


struct Wrapper1
{
    WrapMe& data()& { return member; }
    WrapMe data()&& { return std::move(member); }

    WrapMe member;
};

struct Wrapper2
{
    WrapMe& data()& { return member; }
    WrapMe&& data()&& { return std::move(member); }

    WrapMe member;
};

int main()
{
    auto wrapMe1 = Wrapper1().data();
    auto wrapMe2 = Wrapper2().data();
}

with the output

WrapMe Default Ctor of: 00000092E7F2F8C4
WrapMe Move Ctor of 00000092E7F2F7C4 from 00000092E7F2F8C4
Wrap Me Dtor of00000092E7F2F8C4
WrapMe Default Ctor of: 00000092E7F2F8E4
WrapMe Move Ctor of 00000092E7F2F7E4 from 00000092E7F2F8E4
Wrap Me Dtor of00000092E7F2F8E4
[...]

Which is the correct way to move from the WrapMe member: Like Wrapper1 (return by value) or like Wrapper2 (return by rvalue-reference) does? Or are both ways equivalent here, as the ouput suggests? If not, why?