Since the constructor of std::shared_ptr
is marked as explicit one, so expressions like auto p = std::make_shared<int>(1); p = new int(6);
is wrong.
My question is why does std::make_shared<int>(1); p = nullptr;
compile?
Here is the aforementioned code snippet:
#include <memory>
#include <iostream>
int main()
{
auto p = std::make_shared<int>(1);
//p = new int(6);
p = nullptr;
if(!p)
{
std::cout << "not accessable any more" << std::endl;
}
p.reset();
}
Such code is seen at std::shared_ptr: reset() vs. assignment
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