noexcept function pointers aliases vs typedefs inconsistency

I realized that I can declare a pointer to noexcept function via using, but I am forbidden such declaration if I use a typedef. Consider the code below:

#include <iostream>

using fptr = void(*)() noexcept;
// typedef void(*FPTR)() noexcept; // fails to compile

void f() noexcept
{
    std::cout << "void f() noexcept" << std::endl;
}

void g()
{
    std::cout << "void g()" << std::endl;
    throw 10;
}

int main()
{
    fptr f1 = f;
    fptr f2 = g; // why can we do this?

    try {
        f1();
        f2();
    }
    catch (...)
    {
        std::cout << "Exception caught" << std::endl;
    }
}

If I uncomment the FPTR declaration, I'm getting

error: 'FPTR' declared with an exception specification

However, the using works just fine. My questions are:

1. Why this inconsistency?


2. Why can we even use using with noexcept since we can bind the pointer to functions not declared noexcept, as in the line fptr f2 = g;