How vector elements preserve their original address after a vector std::move?

As you can see in the output, the objects of the vector pre not only "moved" to the vector post, but also preserved their original address space in memory. What is really going on behind this move? Is this behaviour expected? Say I need to have a separate vector of pointers to these objects, is it safe to assume that after this move the objects will always have their original addresses?

Actually, I have a class containing a vector like this and the vector of pointers I mentioned as members. I have also deleted the copy ctors, and defined the move ones for the class.

#include <iostream>
#include <vector>

struct B {
    int val = 0;   
    B(int aInt) : val(aInt) {  };
};

int main() {

    std::vector<B> pre;

    pre.push_back(B(1));
    pre.push_back(B(2));
    std::cout << "pre-move:\t" << (void*)&pre.at(0) << '\n';
    std::cout << "pre-move:\t" << (void*)&pre.at(1) << '\n';

    std::vector<B> post(std::move(pre));

    std::cout << "post-move:\t" << (void*)&post.at(0) << '\n';
    std::cout << "post-move:\t" << (void*)&post.at(1) << '\n';

    return 0;
}

Output:

pre-move:   0x1d7b150 
pre-move:   0x1d7b154 <------|
post-move:  0x1d7b150        |
post-move:  0x1d7b154 <------|