Are conditional expressions in C++ always of bool type?

In C conditional-oriented operators evaluate to either 1 or 0 of type int (even if it does have dedicated _Bool type). Referring to C11 N1570 draft:

C11 §6.5.8/6 Relational operators

Each of the operators < (less than), > (greater than), <= (less than or equal to), and >= (greater than or equal to) shall yield 1 if the specified relation is true and 0 if it is false.¹⁰⁷⁾ The result has type int.

C11 §6.5.9/3 Equality operators

The == (equal to) and != (not equal to) operators are analogous to the relational operators except for their lower precedence.¹⁰⁸⁾ Each of the operators yields 1 if the specified relation is true and 0 if it is false. The result has type int. For any pair of operands, exactly one of the relations is true.

C11 6.5.13/3 Logical AND operator

The && operator shall yield 1 if both of its operands compare unequal to 0; otherwise, it yields 0. The result has type int.

C11 6.5.14/3 Logical OR operator

The || operator shall yield 1 if either of its operands compare unequal to 0; otherwise, it yields 0. The result has type int.

As I checked C++ seems to be different in this matter, as in following example (see http://ift.tt/1t20IP1):

#include <iostream>
#include <typeinfo>

int main() {
    double x = 10.0;

    std::cout << typeid(x <= 10.0).name() << std::endl;

    return 0;
}

outputs b, which as I guess indicates bool type. Does C++ guarantee that all of these operators always evaluate to bool type (in contrast to C)?