std::function with variadic arguments, not templated variable arguments

I basically want to do the following:

typedef
std::function<int(const char* format, ...)> PrintfLikeFunction;

However, that does not seem to work.

Is that possible? I really need to match functions with variadic arguments in my case so that I could pass in printf.

The other reason is, I want to have

void doSomething(PrintfLikeFunction logger);

and the implementation should be separate, thus this must not be a template function.