upcast to a protected base using dynamic_cast

The book The c++ programming language has this code:

class BB_ival_slider : public Ival_slider, protected BBslider {
    // ...
};

void f(BB_ival_slider* p)
{
    Ival_slider* pi1 = p;  // OK
    Ival_slider* pi2 = dynamic_cast<Ival_slider*>(p);    // OK
    BBslider* pbb1 = p;    // error: BBslider is a protected base
    BBslider* pbb2 = dynamic_cast<BBslider*>(p);    // OK: pbb2 becomes nullptr
}

I tried to prove this behavior for better understanding using the following code:

#include <iostream>

class Ival_slider {
public:
    Ival_slider() {
        std::cout << "Ival_slider called" << '\n';
    }
};

class BBslider {
public:
    BBslider() {
        std::cout << "BBslider called" << '\n';
    }
};

class BB_ival_slider : public Ival_slider, protected BBslider {
public:
    BB_ival_slider() {
        std::cout << "BB_ival_slider called" << '\n';
    }
};


int main() {
    BB_ival_slider* p = new BB_ival_slider{};
    Ival_slider* p1 = p;
    Ival_slider* p2 = dynamic_cast<Ival_slider*>(p);
    BBslider* pbb2 = dynamic_cast<BBslider*>(p);
    if (pbb2) {
        std::cout << "true" << '\n';
    }
}

However,

BBslider* pbb2 = dynamic_cast<BBslider*>(p);

seems not to work as expected.

g++ -std=c++11 -O0 -g3 -Wall -c -fmessage-length=0 -o cast.o "..\\cast.cpp"

..\cast.cpp: In function 'int main()':

..\cast.cpp:29:43: error: 'BBslider' is an inaccessible base of 'BB_ival_slider'

BBslider* pbb2 = dynamic_cast(p);

^

..\cast.cpp:29:43: error: 'BBslider' is an inaccessible base of 'BB_ival_slider'

I thought dynamic_cast should at least return nullptr. Is the book wrong? I'm using GCC 4.9.2.