Accessing template arguments from specialization

template<typename T, typename U>
struct A;

template<std::size_t I>
struct A<int, char[I]> {
    using pointer = T*; // does not compile
};

int main() {
    A<int, char[3]> a;    
}

Is there any way to access the type T (= int) from inside the class template specialization A<int, char[I]>, without explicitly writing the type that is has in the specialization?