declare a c++ template object without built-in datatype?

Is there any way to declare a template class object with a datatype that is defined by the user in the main() function?

If yes, how? If no, why and is there an alternative?

For example:

template <class type>
class myclass
{
    type myint;
    type mydouble;
    type mychar;
    type mystring;

public:

    void myint(type);
    void mydouble(type);
    void mychar (type);
    void mystring (type);
};

int main ()
{
    // how can i get data for all different datatype 
    // using only one template class object

    // something like myclass<type>oject;
    object.myint() = 10;
    object.mydouble()=3.5;
    object.mychar()= 'c';
    object.mystring = "myname";

    //obviously this won't work. 

How can I make this work?

I really do not want to use one object for each of them.