Duplicate vector in place (easiest way)

I used a loop, like this:

#include <iostream>
#include <vector>
#include <cstdlib>
using namespace std;

void duplicateVec(vector<int>& v, const int timesOriginalSize = 2)
{
    try {
        const unsigned int vecSize = v.size();
        for(unsigned int i = 0; i < (timesOriginalSize - 1) * vecSize; ++i)
            v.push_back(v[i]);
    }
    catch (const std::bad_alloc&) {
        cerr << "Out of memory! v.size() = " << v.size() << endl;
        exit(EXIT_FAILURE);
    }
}

int main() {
        vector<int> v(10);
        cout << "Before duplicating, v.size() = " << v.size() << endl;
        duplicateVec(v);
        cout << "After duplicating, v.size() = " << v.size() << endl;
        return 0;
}

but I was wondering if there was any easier way to write this..Any ideas?