I wrote a function which takes an N-dimensional std::array
and a parameter pack (coordinates) equal to the number of dimensions of the input std::array
. I already can estimate the size of each dimension of the std::array with a meta function and I wrote a functions counting the parameters in the pack.
I want to 1) generate a new constexpr std::array
with size equal to the number of dimensions of the input std::array
. 2) The array shall be initialized with the size of each dimension of the input std::array. Does someone have a tip how to fill the std::array
right with C++11 only.
E.g. this code
using array3d = std::array<std::array<std::array<int, 4>, 4>, 4>;
3d_helper<array3d>(array3d(), 0,0,0);
Should generate:
constexpr array3d array = { 4, 4, 4 };
Here is what I have so far:
//! Static estimation of std::array container size
// Declare a generic template (which is called initially)
template <size_t dim, class Array>
struct static_size;
// specialization for std::array and first dimension
// creates a struct with a static member "value = N"
template <class T, size_t N>
struct static_size<0, std::array<T, N>> : std::integral_constant<size_t, N> {};
// specialization for std::array and dimension > 0 -> recurse down in dim
template <size_t dim, class InnerArray, size_t N>
struct static_size<dim, std::array<InnerArray, N>> : static_size<dim - 1, InnerArray> {};
template <class FIRST, class... OTHER>
size_t num_args() {
return 1 + num_args<OTHER...>();
}
template <class FIRST>
size_t num_args() {
return 1;
}
template <class ARRAY, class... ARGS>
struct 3d_helper {
static glm::vec3 at_t(const ARRAY &points, ARGS... args) {
constexpr size_t nargs = num_args<ARGS...>();
/*
constexpr size_t n1 = static_size<0, ARRAY>::value - 1;
constexpr size_t n2 = static_size<1, ARRAY>::value - 1;
*/
// ...
using array_t = std::array<size_t, nargs>;
// fill it somehow
}
};
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