One-liner for evaluating pointer-returning function call [duplicate]

This question already has an answer here:

• Can I write this if statement with a variable declaration on one line? 5 answers

Reading this blog bost I understood that the following won't compile:

#include <iostream>

using namespace std;

int* foo() {
    return new int{1};
}

int main()
{
    if (int* a = foo() && *a == 1)
        cout << "yes";
    else
        cout << "no";
}

GCC (http://tpcg.io/UMl20e) gives:

main.cpp: In function ‘int main()’: main.cpp:11:33: error: cannot convert ‘bool’ to ‘int*’ in initialization if (int* a = foo() && *a == 1)

As I have such checks often: Is there an equivalently "beautiful" oneliner for the if condition which does compile?

One possible solution would be

if (int* a = foo()) if(*a == 1)

but this looks somewhat suspicious