I am trying to apply the type_trait has_fun
recursively so that C
enables its fun
member function only if T
has one. Is there a way to make C::fun
being conditionally detected?
template <typename T>
struct has_fun {
template <class, class> class checker;
template <typename U>
static std::true_type test(checker<U, decltype(&U::fun)> *);
template <typename U>
static std::false_type test(...);
static const bool value = std::is_same<std::true_type, decltype(test<T>(nullptr))>::value;
};
struct A {
void fun(){
std::cout << "this is fun!" << std::endl;
}
};
struct B {
void not_fun(){
std::cout << "this is NOT fun!" << std::endl;
}
};
template<typename T>
struct C {
void fun() {
static_assert(has_fun<T>::value, "Not fun!");
t.fun();
}
T t;
};
int main(int argc, char const *argv[])
{
std::cout << has_fun<A>::value << std::endl;
std::cout << has_fun<B>::value << std::endl;
std::cout << has_fun<C<A>>::value << std::endl;
std::cout << has_fun<C<B>>::value << std::endl;
}
Output:
1
0
1
1
Expected output:
1
0
1
0
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