dimanche 6 mai 2018

Return if an expression is invalid or its output in C++

I have a postfix expression and I need to evaluate it also check for its validity. There can be a way in which I first evaluate the expression and if it is valid then I go for its calculation But that involves doing the same work twice. How to do it in a single call?

My code is below where the function works for evaluation and I want to return for error where it is written

//return error

Any help how to proceed with this?

#include<iostream>
#include<stack>
#include<cstring>
using namespace std;

int isOperand(char s){
    if(s >= '0' && s<= '9')
        return 1;
    return 0;
}
int applyOperation(int val1, int val2, char expression){
    switch(expression){
        case '+':
            return val2+val1;
        case '-':
            return val2-val1;
        case '*':
            return val2*val1;
        case '/':
            return val2/val1;
    }
}
int evaluatePostfix(char* exp){
    stack<int> operandStack;

    int l = strlen(exp);
    for(int i=0;i<l;i++){
        if(isOperand(exp[i]))
            operandStack.push(exp[i]-'0');
        else{
            if(operandStack.empty())
                //return error
            int val1 = operandStack.top();
            operandStack.pop();
            if(operandStack.empty())
                //return error
            int val2 = operandStack.top();
            operandStack.pop();
            int result = applyOperation(val1,val2,exp[i]);
            operandStack.push(result);
        }
    }
    int topElem = operandStack.top();
    operandStack.pop();
    if(!operandStack.empty())
        //return error
    return operandStack.top();
}

int main()
{
    char exp[] = "231*+9-";
    printf ("Value of %s is %d", exp, evaluatePostfix(exp));
    return 0;
}

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