I am trying to write a regular expression which recognises whitespaces from a user input string, except for between quotation marks ("
..."
). For example, if the user enters
#load "my folder/my files/ program.prog" ;
I want my regex substitution to transform this into
#load "my folder/my files/ program.prog" ;
So far I've implemented the following (you can run it here).
#include <iostream>
#include <string>
#include <regex>
int main(){
// Variables for user input
std::string input_line;
std::string program;
// User prompt
std::cout << ">>> ";
std::getline(std::cin, input_line);
// Remove leading/trailing whitespaces
input_line = std::regex_replace(input_line, std::regex("^ +| +$|( ) +"), "$1");
// Check result
std::cout << input_line << std::endl;
return 0;
}
But this removes whitespaces between quotes too. Is there any way I can use regex to ignore spaces between quotes?
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