Range-based for loop on a temporary range

Thanks to some segmentation faults and warnings in valgrind, I found that this code is incorrect and has some sort of dangling reference in the for-range loop.

#include<numeric>
#include<vector>

auto f(){
    std::vector<std::vector<double>> v(10, std::vector<double>(3));
    iota(v[5].begin(), v[5].end(), 0);
    return v;
}

int main(){
    for(auto e : f()[5])
        std::cout << e << std::endl;
    return 0;
}

It looks as if the begin and end is taken from a temporary and lost in the loop.

Of course, a way around is to do

    auto r = f()[5];
    for(auto e : r)
        std::cout << e << std::endl;

However, I wonder exactly why for(auto e : f()[5]) is an error and also if there is a better way around or some way to design f or the even the container (std::vector) to avoid this pitfall.

With iterator loops is more obvious why this problem happens (begin and end come from different temporary objects)

for(auto it = f()[5].begin(); it != f()[5].end(); ++it)

But in a for-range loop, as in the first example, it seems very easy to make this mistake.