Will this do default move operation

I have a function foo:

std::vector<T> foo() {
  std::vector<T> result;
  // populate result
  {
    /*
       for loop with result.push_back().
       ignore real code.
    */
  }
  //
  return result;    <-- note there without std::move
}

Will it do extra copy if I assign like the following?

const auto v = foo();   <-- will it move the vector by default?
const auto &v = foo();  <-- same question as above, assuming T is movable