Here is an array and I am finding integrals of a desired row , How to get this result in double form?

Here is a Pascal's triangle . After the output of the array , user chooses a row to be integrated . There is another loop for integration but I get the answer in int form . And the required answer needs to be in double form . If I change int to double then all the code just mixes with double and int.Below is the array
1
1 1
1 2 1
1 3 3 1 ------> For this I need the answer stated below
1 4 6 4 1

Code

#include <iostream>

using namespace std;

int main() {

    int integ, row_nb, pascal; 
    const int rows = 5;
    const int columns = 5;
    double integrals, P;


    int **array = new int *[rows]; //generating array
    for (int i = 0; i <= rows; i++)
        array[i] = new int[columns];

    for (int i = 0; i <= rows; i++) {  //loop for te pascal's triangle
        for (int j = 0; j <= i; j++) {
            if (j == 0 || i == 0) {
                pascal = 1;  //first element of pascal's triangle
            }
            else {
                 pascal = pascal *(i - j + 1) / j; //pascal's triangle formula
            }
            array[i][j] = pascal; 
            cout << "  " << pascal; 
        }
        cout << "\n";
     }

    cout << "enter which row to intergrate: "; // loop for the desired array
    cin >> row_nb; 

    cout << "P(x) = ";                        //loop for p(x)
    for (int i = 0; i < row_nb + 1; i++) { 
        cout <<array[row_nb][i] << " ";
    }
    cout << "\n";
    cout << "f P(x) = "; 

    for (int i = 0; i < row_nb + 1; i++) {          
        cout << (array[row_nb][i]) / (i + 1) << " "; // loop for the result 
                                                     // (but i want this result in double form rather than int )
    }


    return 0; 
}

For example , for 1,3,3,1 I get the answer 1,1,1,0 BUT the answer should be 1, 1.5, 1, 0.5