I'm trying to get my head around how constexpr work. And I need to convert a lot of code from const to constexpr. But I've hit a problem where I cant see the solution.
I have the following class:
class Control_base
{
public:
static constexpr Control_base high_clock();
static constexpr uint8_t size();
static const Control_base from_index(uint8_t index_);
Control_base& operator=(const Control_base& rhs) = default;
constexpr Device_address value() const;
private:
constexpr explicit Control_base(Device_address value_);
Device_address value;
};
constexpr Control_base::Control_base(Device_address value_) :
value(value_) {}
constexpr Device_address Control_base::value() const { return value; }
inline const Control_base Control_base::high_clock() { return Control_base(reinterpret_cast<Device_address>(0x10009000)); }
typedef const Control_base (*Control_base_func)(void);
const Control_base_func Control_base_arr[] = {&Control_base::high_clock};
inline const Control_base Control_base::from_index(uint8_t index_)
{
return Control_base_arr[index_]();
}
constexpr uint8_t Control_base::size() { return 1; }
};
I wish to make the following changes:
From
inline const Control_base Control_base::high_clock() { return Control_base(reinterpret_cast<Device_address>(0x10009000)); }
typedef const Control_base (*Control_base_func)(void);
const Control_base_func Control_base_arr[] = {&Control_base::high_clock};
To
constexpr Control_base Control_base::high_clock() { return Control_base(reinterpret_cast<Device_address>(0x10009000)); }
typedef const Control_base (*Control_base_func)(void);
constexpr Control_base_func Control_base_arr[] = {&Control_base::high_clock};
However, I get the following error in
constexpr Control_base_func Control_base_arr[] = {&Control_base::high_clock};
^
**value of type "ns::Control_base (*)()" cannot be used to initialize an entity of type "const ns::Control_base_func"**
I can't figure out what the best solution is here. And why it works with const but not constexpr
Regards
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