I have the following piece of code:
#include <iostream>
struct T {
int a;
T() = default;
T(T& other) {
std::cout << "copy &\n";
}
T(T&& other) {
std::cout << "move &&\n";
}
};
void foo(T&& x) {
T y(x); // why is copy ctor called??????
}
int main() {
T x;
foo(std::move(x));
return 0;
}
I don't understand why copy constructor is preferred over move constructor even though foo()
accepts rvalue-reference.
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