the final test case says to output the word "Tie" when there is 2 or more cows who produce the second-least amount of milk. In my program, i clearly wrote a program for that case. here is the code, if it helps
#include <bits/stdc++.h>
using namespace std;
int main()
{
freopen("notlast.in","r", stdin);
freopen("notlast.out","w", stdout);
int n,values;
cin>>n;
int cowvalues[7]={0};
string cowss[n],cows[7]={"Bessie", "Elsie", "Daisy", "Gertie", "Annabelle", "Maggie", "Henrietta"};
for(int i=0;i<n;++i){
cin>>cowss[i]>>values;
for(int j=0;j<7;++j){
if(cowss[i]==cows[j])
{
cowvalues[j]+=values;
}
}
}
for(int i=0;i<6;++i){
for(int j=0;j<6-i;++j){
if(cowvalues[j]>cowvalues[j+1])
{
swap(cowvalues[j],cowvalues[j+1]);
swap(cows[j],cows[j+1]);
}
}
}
int a=1;
while(cowvalues[a]==cowvalues[0]) a++;
if(cowvalues[a+1]==cowvalues[a]) cout<<"Tie\n";
else cout<<cows[a]<<"\n";
}
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