I am somewhat confused about the following piece of code. How can b still reference a but have a different value?
#include <iostream>
using namespace std;
int main()
{
const int a = 5;
const int &b = a;
++(int&)b;
cout << a << endl;//returns 5
cout << b << endl;//returns 6
cout << "mem a:" << &a << endl; //returns 0x61ff18
cout << "mem b:" << &b << endl; //returns 0x61ff18
return 0;
}
Aucun commentaire:
Enregistrer un commentaire