The statement
Implicitly-declared move assignment operator
If no user-defined move assignment operators are provided for a class type (struct, class, or union), and all of the following is true:
there are no user-declared copy constructors;
there are no user-declared move constructors;
there are no user-declared copy assignment operators;
there are no user-declared destructors;
with user-declared copy assigment operator does it means only
class_name & class_name :: operator= ( class_name && )
or any operator=()
defined?
Example:
class Bar
{
public:
Bar() = default;
SomeClass some;
};
class Foo
{
public:
Foo() = default;
Foo& operator=(Bar&& bar) : some(std::move(bar.some))
{
}
SomeClass some;
};
Does that match the condition for an implitely-declared move assigmnent operator?
The same goes for the implicitly-declared move constructor.
Aucun commentaire:
Enregistrer un commentaire