NO Idea, why the base string get return instead of Derived, is that becasue vector copied only base object from the dervied object? [duplicate]

NO Idea, why the base string get return instead of Derived, is that becasue vector copied only base object from the dervied object?

#include <vector>
#include <iostream>
using namespace std;
class Base
{
protected:
    int m_value{};
 
public:
    Base(int value)
        : m_value{ value }
    {
    }
 
    virtual const char* getName() const { return "Base"; }
    int getValue() const { return m_value; }
};
 
class Derived: public Base
{
public:
    Derived(int value)
        : Base{ value }
    {
    }
 
    virtual const char* getName() const { return "Derived"; }
};

int main()
{
    std::vector<Base> v{};
    v.push_back(Base{ 5 });
    v.push_back(Derived{ 6 });
 
        
    for (const auto& element : v)
        std::cout << "I am a " << element.getName() << " with value " << element.getValue() << '\n';
 
    return 0;
}

why in second output Base is get return from the getName() methods?

Is that because of vector is not a pointer type or reference?

I am a Base with value 5

I am a Base with value 6 ----> why it prints the Base?