Why is the pointer displaying the value and not the address?

I have this code:

int *array_ptr{nullptr}; 
array_ptr = new int[10]; // allocate array on the heap
    
for(int i=0; i<10; i++){
    array_ptr[i] = i;
    std::cout<<array_ptr[i]<<std::endl;
}

delete [] array_ptr; // deletes allocated space

To my understanding, int *array_ptr displays the actual value, whereas int array_ptr with no dereference operator displays the address in memory.

So, how come array_ptr[i] displays 0 1 2 3 4 ... 10, instead of displaying address 1000, 1004, 1008...etc. (address nr made up).