After calling destructor why member function will be called [duplicate]

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• C++ delete - It deletes my objects but I can still access the data? 11 answers

I am not getting run time exception/error on below code. I called the member function Display() after destroying the object. Then why it still calls the function Display instead of compiler error? I am using Dev C++ ide.

Thanks in advance.

#include< iostream>
#include< string>
using namespace std;

class Sample
{


int count ;

public:
    void Display()
    {
        cout << count << endl;
        cout << "Inside Sample::Display" << endl;
    }
};

int main()

{

Sample *ob = new Sample();

delete ob;

ob->Display();

return 0;   
}