Can one assume in unevaluated context, that (::new (std::declval< void * >()) T())->~T()
is semantically full equivalent to simple T()
? Assume neither global, nor class-scope operator new
are not overloaded, if it mutters much.
Often in type traits T()
used inside operator noexcept()
to determine whether only the separate constructor is noexcept
or not. Surely it is wrong.
To prevent the loss of generality one can assume that T()
here is either a calling of a default constructor or of any other constructor.
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