I am having a bit of a struggle with Microsoft Visual C++ 2015 and was able to replicate the issue with a small program. Given the following classes:
class BaseClass {
public:
BaseClass()
: mValue( 0 )
, mDirty( true )
{}
virtual ~BaseClass() {}
virtual int getValue() const { if( mDirty ) updateValue(); return mValue; }
protected:
virtual void updateValue() const = 0;
mutable bool mDirty;
mutable int mValue;
};
class DerivedClass : public BaseClass {
public:
DerivedClass() {}
protected:
void updateValue() const override
{
mValue++;
mDirty = false;
}
};
class Impersonator {
public:
Impersonator() {}
// conversion operator
operator DerivedClass()
{
return DerivedClass();
}
};
I get a "pure virtual function call" error when I do the following:
void use( const BaseClass &inst )
{
// calls `getValue` which in turns calls the virtual function 'updateValue'
int value = inst.getValue();
}
int main()
{
// creates a temproary, then passes it by reference:
use( DerivedClass() ); // this works
// calls conversion operator to create object on stack, then passes it by reference:
DerivedClass i = Impersonator();
use( i ); // this works
// calls conversion operator to create a temporary, then passes it by reference:
Impersonator j = Impersonator();
use( j ); // causes a pure virtual function call error!
return 0;
}
Given that I can't change the void use(const BaseClass&)
function, can I change anything in the Impersonator
class to allow using the third call without generating a debug error?
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