I was trying to swap two variables using std::tie()
as per the following code (I am aware of std::swap
, I was just trying this out of curiosity):
#include <iostream>
#include <tuple>
using std::cin; using std::tie;
using std::cout; using std::endl;
using std::make_pair;
int main() {
int a = 2, b = 10;
cout << "Before Swapping using {}" << endl;
cout << "a: " << a << " b: " << b < <endl;
tie(a, b) = {b, a};
cout << "After Swapping using {}" << endl;
cout << "a: " << a << " b: " << b << endl;
a = 2, b = 10;
cout << "Before Swapping using make_pair()" << endl;
cout << "a: " << a << " b: " << b << endl;
tie(a, b) = make_pair(b, a);
cout << "After Swapping using make_pair()" << endl;
cout << "a: " << a << " b: " << b << endl;
return 0;
}
I compiled it using g++ test.cpp -std=c++11 -o test
.
But the output was this:
Before Swapping using {}
a: 2 b: 10
After Swapping using {}
a: 10 b: 10
Before Swapping using make_pair()
a: 2 b: 10
After Swapping using make_pair()
a: 10 b: 2
So, my question is, since we can write {a, b}
instead of writing std::make_pair(a, b)
everytime (C++11 onwards), why are these two versions giving different output?
My guess was that the following line
std::tie(a, b) = {b, a};
is not making a pair and for some reason only mutating the value of a
. But I am not sure.
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